Board Thread:Internal management/@comment-1764483-20160131204339/@comment-24024415-20160203112651

Iamarepeater wrote: Legofan9o5 wrote: Here are the voting standings (holy Guacodiles, this was repetive as heck to. Like, my entire brainstorm for replacements for the rule took less time to create than THIS):

Beurocrat: 0 (1 Oppose by Someone456, 1 Support by Brainulator9, 1 neutral for Starfruity; leading to an overall voting average of 0 for both sides)

Admin: 2 Support (Itsleo20, Bearjedi support, no oppose)

Content Moderator: 1 Support (Dekagamer7X9, Murabito support, ThisUserLikesOreo oppose)

Discussion Moderator: 2 Support (Lily8763cp, Pinkgirl234 support fully, Microphone_DJ_125 may have forfeited, need confirmation)

Chat Moderator: 1 Support (Insert Your Name Here, Xenons support, Mage General Chrysalis opposes)

Rollback: 2 Support (ADVERT-UR-TRON, Gargantuar333 support, no oppose)

Normal User: 1 Support (IG Gaming + Maramok= Awesome, Legofan9o5, Iamarepeater and DatDramaPlant support, Pmhpc, AWikiBoy521 and Rt genius0702 oppose)



Positive=Support, Negative=Oppose

Using weight (still in effect until vote is passed) of all Beuro and Admins to have +3, Mods and Rollbacks have +2 and others to have 1.

As far as support goes: 1 vote(3 weight) + 2 votes(3 weight) + 2(2) + 2(2) + 2(2) + 2(2) + 4(1) =

3 + 6 + 5 groups(4 votes each) = 29

Total Possible points: 6 + 6 + 6 + 4? (possibly 6) + 6 + 4 + 7 = 39

29/39 = 0.7435897... =74% of the vote (that is either Support or Oppose).

Conclusion: Does Neutral count toward total? Otherwise it's like saying Support Oppose and Oppose, which is very difficult to execute votes and an absolute nightmare to calculate. Plus DJ's vote will be counted as neutral until otherwise corrected by DJ himself.

<p style="font-weight:normal;">As always, any errors I may have made will be corrected, so keep a critical eye on this list. Ignore any neutral or disputed votes. Will that do? Sure, I don't want to scroll down this page 10+ more times just to see who voted neutral, the position of power of those neutral and calculate that into the total again. Too much work already went through for one simple task. x_x